# AsterWell — Industrial Operations Modelling

> Drilling duration, fuel and carbon estimation using interval, penetration-rate and nonproductive-time assumptions. Not logistics dispatch, well control or operational safety guidance.

- Canonical URL: https://mkworks.co.business/
- Methodology & Equations: https://mkworks.co.business/methodology/
- Interactive Browser Runtime: https://mkworks.co.business/run/
- Author & Root Entity: Mohammad Rezwan Khan, PhD (https://mrkhan.co.technology/#person)
- Ecosystem Directory: https://mklab.co.technology/
- Knowledge Graph JSON-LD: https://mkworks.co.business/knowledge-graph.jsonld

## Governing Mathematical Formulation & Units
- Formula: `Drilling Time T_drill = Interval (m) / ROP (m/h); Total Duration T_total = T_drill / (1 − NPT_pct/100); Fuel (L) = T_total × Fuel_Rate (L/h); Emissions (tCO2e) = Fuel (L) × EF (kgCO2e/L) / 1,000; Cost = Fixed_Cost + (T_total / 24) × Daily_Rate`
- Units: Interval in metres (m); rate of penetration (ROP) in m/h; nonproductive time (NPT) in %; duration in hours (h) and days (d); fuel in litres (L); carbon emissions in metric tonnes CO2e (tCO2e); cost in assumed USD.

## Reproducible Worked Example
Case 1 (800 m interval, ROP = 10 m/h, NPT = 10%, Daily Rate = 24,000 USD/d, Fixed Cost = 50,000 USD, Fuel Rate = 180 L/h, EF = 2.68 kgCO2e/L): Net drilling time = 80.0 h; with 10% NPT, T_total = 80 / 0.9 = 88.89 h (3.704 days). Total Fuel = 88.889 × 180 = 16,000 L; Emissions = 16,000 × 2.68 / 1,000 = 42.88 tCO2e; Estimated Cost = 50,000 + 3.7037 × 24,000 = 138,888.89 USD.

## Canonical Companion Modules on this Domain
- **MinuteHarbor** (https://mkworks.co.business/minuteharbor/): Integer-cent allocation and reconciliation on fictional meeting records. Boundary: Not a certified accounting system, legal compliance or live organizational records.